Gisela, Blade of Goldnight and Mirror Gallery

Asked by pandabear 13 years ago

if i have Mirror GalleryMTG Card: Mirror Gallery and multiple Gisela, Blade of GoldnightMTG Card: Gisela, Blade of Goldnight out on the battlefield, do the damage halving and damage multiplying abilities compound or are they one flat rate???? cuz it would be a really cool combo especially with an Infinite ReflectionMTG Card: Infinite Reflection!

The OBjection says... #1

As best as I can tell, much as in the same scenario as if a player controlled two Doubling SeasonMTG Card: Doubling Season or two Fire ServantMTG Card: Fire Servant, your opponents would take 4x the damage they would with no Giselas out.

April 20, 2012 10:07 p.m.

linkofhyrule says... #2

The same would go for the reduction, I think... x2 is quartered, x3 is an eighth, and x4 would be 1/16th damage (and beyond for copy-tokens)

April 20, 2012 10:48 p.m.

linkofhyrule says... #3

err... you halve the damage with #1, then halve it again with #2, halve again with #3, again with #4, and so on, if you clone/copy her

April 20, 2012 10:51 p.m.

CrushU says... Accepted answer #4

Gisela, Blade of GoldnightMTG Card: Gisela, Blade of Goldnight has two abilities that set up Replacement Effects. In both cases, multiple abilities will stack, causing x4 damage dealt and /4 damage received, although it's a bit complicated as you halve and round up twice instead.

For example, if you would deal 5 damage, the first Gisela says you deal 10 damage instead, so now you're dealing 10 damage and the first Gisela has replaced the event so will no longer replace it. The second Gisela now replaces the event 'deal 10 damage' with 'deal 20 damage'. And so on and so forth.

If you would receive 5 damage, the first Gisela halves, and rounds up, to 3 damage. The second halves, and rounds up, to 2 damage.

April 21, 2012 9:15 a.m.

linkofhyrule says... #5

@CrushU:

the specific wording is that Gisela, Blade of GoldnightMTG Card: Gisela, Blade of Goldnight prevents half, rounded up. She will prevent 3 out of 5, then of the two remaining, the next will prevent 1 out of 2, and of the 1 remaining, the third will prevent "1/2", rounded up to "1", thus in order to take any damage you'd need to be dealt at least...

(works out math...) taking 1 damage:

fourth Gisela: must have 2 damage remaining

third Gisela: must have 4 damage remaining

second Gisela: must have 8 damage remaining

first Gisela: must have taken at least 16 damage

So, in order to take a single point of damage, your opponent will have to hit for 16 damage. It gets much larger for each additional point of effective damage, after all the halving.

April 21, 2012 2:10 p.m.

CrushU says... #6

You are correct on the halving.

April 21, 2012 2:12 p.m.

linkofhyrule says... #7

The only way I can see anyone managing to win against this is an infinite combo'd FireballMTG Card: Fireball, to deal ~320 damage to the player...doing the math: 20 - 40 - 80 - 160 - 320

April 21, 2012 2:23 p.m.

CrushU says... #8

April 21, 2012 3:06 p.m.
April 21, 2012 4:57 p.m.

pandabear says... #10

that is awesome!!!! thanks for the lucid explanations guys! and girls if u r one :p

April 21, 2012 8:13 p.m.

acronix says... #11

All of you are wrong. Gisela is a legendary creature. The legendary rule prevents there being more than one Gisela on the field at any point in time.

April 22, 2012 1:22 p.m.

acronix says... #12

Oh nevermind I didnt see Mirror GalleryMTG Card: Mirror Gallery. My bad.

April 22, 2012 1:23 p.m.

This discussion has been closed