Brudiclad, Telchor Engineer with tokens that will leave play (Flameshadow Conjuring)
Asked by ptownazkikr 5 years ago
If I make a token copy of a creature with Flameshadow Conjuring and turn all of my tokens into a copy of it with Brudiclad, Telchor Engineer, will all of my tokens be exiled at the end of my turn?
ptownazkikr says... #2
Thank you for the answer but can you help me understand why its exile trigger isn’t copied while almost everything else about the original token is applied to the new copies of it?
August 13, 2018 4:39 p.m.
Gidgetimer says... Accepted answer #3
706.2. When copying an object, the copy acquires the copiable values of the original object’s characteristics and, for an object on the stack, choices made when casting or activating it (mode, targets, the value of X, whether it was kicked, how it will affect multiple targets, and so on). The “copiable values” are the values derived from the text printed on the object (that text being name, mana cost, color indicator, card type, subtype, supertype, rules text, power, toughness, and/or loyalty), as modified by other copy effects, by its face-down status, and by “as . . . enters the battlefield” and “as . . . is turned face up” abilities that set power and toughness (and may also set additional characteristics). Other effects (including type-changing and text-changing effects), status, and counters are not copied.
As you can see from the rule that defines what is copied, the delayed trigger that was created as a part of Flameshadow Conjuring resolving is not a copiable characteristic. If the effect were part of the text of the card such as on Ball Lightning then the copies would be affected.
August 13, 2018 5:04 p.m.
The exile effect is a delayed triggered ability created by Flameshadow Conjuring, not by the token, and only referring to that specific token. Copies made with Brudiclad, Telchor Engineer only copy what's written on the token itself, which does not include that delayed triggered ability. It also doesn't include haste, as that was also granted by the Conjuring and not part of the token itself.
At the beginning of the next end step, that delayed triggered ability will finally trigger and look for the specific token made with that copy of Flameshadow Conjuring. If it can't find it somehow (phasing?) or is countered, the token can remain on the battlefield indefinitely.
Specific ruling from the Gatherer from Flameshadow Conjuring, for good measure:
6/22/2015: If another creature becomes or enters the battlefield as a copy of the token, that creature won't have haste and it won't be exiled.
August 13, 2018 5:05 p.m.
Rhadamanthus says... #5
I can see that other responses popped in while I was typing, but here's my summary of the details anyway: A copy effect only copies what's called the "copiable characteristics". For a card, the copiable characteristics are whatever's written on the original. For a token, they're the specific characteristics given to the token when it was originally created. Nothing else is copied. It's also important to note that once a card/token becomes a copy of something else, those new characteristics become its copiable characteristics.
Because of the way Flameshadow Conjuring is written, the "that token gains haste" and "exile it at the beginning of the next end step" parts of the effect aren't part of the token's copiable characteristics. They won't get copied by anything that copies the token. If the text of Conjuring was written more like "put a token onto the battlefield that's a copy of that creature, except it has haste and 'at the beginning of the end step, exile this creature'", then it would be copiable.
Neotrup says... #1
No. Only the token created by Flameshadow Conjuring will be exiled.
August 13, 2018 4:24 p.m.