Why do some cards have multiple x's?
Asked by Halphinianian 8 years ago
I was wondering what the purpose of the multiple 's on certain cards such as Astral Cornucopia, Hangarback Walker, and Bonfire of the Damned. The extra ones must be there for a reason, but I have no idea what that reason is?
Could I just pay for Astral Cornucopia and have it enter the battlefield with 1 charge counter? And what about Hangarback Walker? I have no idea how this works
I have seen other people try to explain it in other questions here, but none of them have really made sense to me
When casting you pick a value for X. Then all instances of X on the card are represented by that number. If multiple X's appear in the casting cost, you must pay the value of X for each time it appears.
for Astral Cornucopia: You have to pay 3 times the vlaue of X, since x appears 3 times.
if you pick X as 1 you would have to pay 3 mana. (3 x 1 = 3)
if you pick X as 2 you would have to pay 6 mana. (3 x 2 = 6)
And so forth.
April 3, 2016 10:21 p.m.
Raging_Squiggle says... #3
When casting a spell that has in its mana cost, you declare the value for then pay the cost. If multiple 's are in the mana cost, you must pay for each one.
For example:
you declare 5 for the in Endless One's cost. Then you must pay mana.
you declare 5 for Chalice of the Void. Since it has 2 's in its cost, you must pay for a total of mana.
you declare 5 for Astral Cornucopia. Since it has 3 's in its cost, you must pay for a total of mana.
Essentially, for each in the mana cost, you must pay the declared amount times the number of 's.
rainbowofdeath says... #1
when u pick it all af the x's have to be equal to eachother, so if u want astral conucopia x to equal one u have to pay three because u have to pay the same amount for each x, and if u want hagarback to equal one u have to pay two, because each x has to be the same, does that make sense?
April 3, 2016 9:22 p.m.