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Format | Legality |
1v1 Commander | Legal |
Alchemy | Legal |
Archenemy | Legal |
Arena | Legal |
Block Constructed | Legal |
Brawl | Legal |
Canadian Highlander | Legal |
Casual | Legal |
Commander / EDH | Legal |
Commander: Rule 0 | Legal |
Custom | Legal |
Duel Commander | Legal |
Gladiator | Legal |
Highlander | Legal |
Historic | Legal |
Legacy | Legal |
Leviathan | Legal |
Limited | Legal |
Modern | Legal |
Oathbreaker | Legal |
Pioneer | Legal |
Planechase | Legal |
Pre-release | Legal |
Quest Magic | Legal |
Standard | Legal |
Tiny Leaders | Legal |
Vanguard | Legal |
Vintage | Legal |
Widespread Thieving
Enchantment
Hideaway 5 (When this enchantment enters the battlefield, look at the top five cards of your library, exile one face down, then put the rest on the bottom in random order.)
Whenever you cast a multicoloured spell, create a Treasure token. Then you pay . If you do, you may play exiled card without paying its mana cost. (This is a linked ability, linked to the ability in the first paragraph on the card named "Widespread Thieving". You may only cast cards exiled by this card if they were exiled by the ability in the first paragraph.)
Rhonir on Questions regarding color identity/color interaction
1 year ago
Good day,
I'm building a Jodah, Archmage Eternal deck and have two questions regarding the alternative cost and color identity of Jodah.
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As far as I understand it, Jodah's ability sets the cmc for a spell to WUBRG for the action "casting". After resolving the spell gets back its former cmc and therefore colorization. Is it right that cards like Obsidian Obelisk, Mana Cannons and Widespread Thieving therefore interact with spells that I cast for WUBRG although they are monocolored since those cards interact with the "casting" action?
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If I have those two permanents on the battlefield: Faeburrow Elder and Jodah, Archmage Eternal. Does Faeburrow Elder give me WURG (WUR from Jodah, G from Faeburrow Elder) or WUBRG from Jodah's color identity?
Many thanks in advance and I hope this is the right forum for these questions.
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