Casting X Spells with cost reducers

Asked by mrrndublebarrel 4 years ago

Let's say i have God-Eternal Kefnet on the battlefield. I draw Torment of Hailfire . I reveal it and pay two black and X=0. The spell costs 2 less to cast from Kefnet's ability. Will X=2 or will it still be X=0?

Rhadamanthus says... #1

If you actually chose X=0 then X=0. In the steps of casting a spell, you choose the value of any X before calculating the total cost.

In this example, if you want X=2 then you would choose X=2 while casting the spell and then calculate the total cost as - =

May 15, 2019 9:56 a.m.

Would I still have to pay mana to choose 2?

May 16, 2019 2:41 a.m.

Boza says... Accepted answer #3

No. When casting a spell or activating an ability, one of the first things you do is you make the necessary choices, including how large an X you want. Then you calculate how much mana it would cost you to cast the spell using this equation:

Mana cost of the spell + cost additions - cost reductions = actual mana you need to pay

So for this case, if you select X=2, the equation would look like:

mana cost of the spell + cost additions - cost reductions = actual mana to be paid

In the end, you will get to cast a 4 CMC Torment of Hailfire , with x=2, but only pay for it.

May 16, 2019 4:33 a.m.

Thank you all, very much.

May 16, 2019 12:57 p.m.

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