while i have an Emerald Medallion on the field when I cast Mistcutter Hydra with 6 mana,will it get 5 counters or 6?
Asked by koylucumert 9 years ago
I know it does not decrease the colored cost but I am wondering if it is treated as 1 mana for X or not
filledelanuit says... #2
The simplified steps of casting a spell determine how much you pay.
Announce the Spell and put it on the stack
Choose the modes then declare what x values you want. Ex. X=6.
The costs are set. First there is the original cost. Then cost additions, subtractions and finally cost setting effects. Ex Trinisphere. I. You case you could declare x=6. The total cost would be 6G but Emerald Medallion would reduce it to 5G. So you have have to pay 6 mana total.
Then it is put onto the stack with its modes chosen and x costs set.
TL;DR: 6 counters
November 25, 2014 4:20 p.m.
Absinthman says... #3
Just a note: It is not unusual for players to think that you first dump your mana into an "X" spell and then the value of X is determined based on how much mana you put in it. But it is actually the other way around. First you set the value of X, and that tells you how much mana you have to pay.
November 25, 2014 4:22 p.m.
This is so infuriating. My brother and I were told countless times that X has to be paid first, not declared. I just got the Mizzix commander and read the "Playing the Deck" portion and saw that. Now that I'm looking it up, me and my bro are ticked by thinking about the several times a Hydra or spell could of been loads cheaper.
Absinthman says... Accepted answer #1
When you cast a spell with X in its cost, you declare what is your desired value of X. Then you pay the required mana. If there is an effect that reduces or increases the cost of spells, it is applied after you've chosen what the value of X will be. So in this instance, you can declare the value for X to be 6. Now, the total cost of that spell would normally be 6G, but because of your Medallion, it will be reduced to 5G.
November 25, 2014 4:15 p.m.