Manabarbs

Asked by Wabbbit 13 years ago

If I have three ManabarbsMTG Card: Manabarbs and they play a HellriderMTG Card: Hellrider, does my opponant take 12? Thanks

eze01 says... #1

If you tap 4 mana for HellriderMTG Card: Hellrider you would be the one taking 12.

April 3, 2012 7:57 p.m.

GoblinsInc says... #2

Yes. If you control 3 manabarbs, each one will trigger when a player taps a land. Since your opponent is playing a hellrider then, assuming no mana shenanigans, he will take 12 damage (4 from each barbs)

April 3, 2012 8 p.m.

STG says... #3

If they tapped lands for mana to cast HellriderMTG Card: Hellrider, then yes, your opponent would take 12 damage - 3 damage per land tapped.

April 3, 2012 8:01 p.m.

eze01 says... #4

I read your question wrong sorry. So yes they would take 4 from each barbs.

April 3, 2012 8:08 p.m.

STG says... #5

Hang on a sec. Don't you guys mean 3 from each barb?

Theres 3 ManabarbsMTG Card: Manabarbs on the field, for each land being tapped there are 3 instances of the effect occuring - 1 damage per instance.

4 mana is required to play HellriderMTG Card: Hellrider, that means 4 lands need to be tapped (unless there are other mana producing things going on of course.)

3 (ManabarbsMTG Card: Manabarbs effects) x 4 (Lands tapped) = 12

Sorry, I know I'm being really pedantic about it haha.

April 3, 2012 8:13 p.m.

mistory says... Accepted answer #6

To continue with the pedanticalness, they would actually take 4 damage from each ManabarbsMTG Card: Manabarbs because 4 lands are being tapped.

4 damage per ManabarbsMTG Card: Manabarbs x 3 ManabarbsMTG Card: Manabarbs = 12 damage.

lol.

April 3, 2012 8:44 p.m.

STG says... #7

Wait wait, my Engrish made me derpy.

"Don't you guys mean 3 from each barb?"

"3 from each barb"

-facepalm-

I did not mean that in my head whilst writing, lol.

April 3, 2012 9:02 p.m.

sleepingzach says... #8

but you would lose 12 life just playing the extra 2ManabarbsMTG Card: Manabarbs

April 5, 2012 3:19 p.m.

mistory says... #9

True, but that isn't the question.

April 5, 2012 3:42 p.m.

This discussion has been closed