Excactly which damage is prevented?
Asked by hyena69 7 years ago
Let us say I am attacking my opponent with a Trained Caracal and a Savannah Lions (meow) and he responds by using an Amulet of Kroog to prevent one damage, which damage is prevented? One of the damage from the lion or the lifelink damage from the caracal?
Thanks
@Raging_Squiggle and hyena69 - You are mis-interpreting the rule. The rule states:
If damage would be dealt to the shielded creature or player by two or more applicable sources at the same time, the player or the controller of the creature chooses which damage the shield prevents.
Which means the target of the amulet determines which is prevented. As he is the shielded player, and if the target was a creature than it would be that creatures controller who determined which was damage was prevented.
February 15, 2017 10:41 p.m.
Raging_Squiggle says... #4
I'm not misinterpreting the rule, I instead misread the scenario. I thought you were being attacked and therefore targeting yourself with the amulet.
What I meant to say was the opponent will decide which 1 damage to prevent, since your opponent is the one preventing the damage to himself.
Raging_Squiggle says... Accepted answer #1
615.7. Some prevention effects generated by the resolution of a spell or ability refer to a specific amount of damagefor example, Prevent the next 3 damage that would be dealt to target creature or player this turn. These work like shields. Each 1 damage that would be dealt to the shielded creature or player is prevented. Preventing 1 damage reduces the remaining shield by 1. If damage would be dealt to the shielded creature or player by two or more applicable sources at the same time, the player or the controller of the creature chooses which damage the shield prevents. Once the shield has been reduced to 0, any remaining damage is dealt normally. Such effects count only the amount of damage; the number of events or sources dealing it doesnt matter.
You choose which source of damage is prevented.
February 15, 2017 10:15 p.m.