Multiple blocking, w/ and w/o trample
Asked by Burl 12 years ago
1) I have a 7/7 GR Beast. My opponent blocks with 3 3/3 B Zombies. What happens?
2) I have a 7/7 GR Beast with Trample. My opponent blocks with 3 3/3 B Zombies. What happens?
3) I have a 3/3 GR Beast. My opponent blocks with 2 1/2 W Soldiers and 2 2/2 B Zombies. What Happens?
Okay, what if I have a 3/3 Beast and they block with 2 0/4 and a 1/3. What happens?
March 22, 2014 10:58 p.m.
Okay, what if I have a 3/3 Beast and they block with 2 0/4 and a 1/3. What happens?
You can assign the 3 damage to any one of the creatures, so hitting the 1/3 would probably be best. Your creature won't die.
And they have 0/3 3/2 0/2, I have a 2/3
You can assign 2 damage; you can kill the 3/2 or the 0/2, but the 0/3 will live in any case. Your creature will die from the 3/2.
Trample just ("just") means that if your creature's power is greater than the combined toughness of the blocking creatures, extra damage can get dealt to the defending player.
For example, in scenario 2 of your original creature, if your 7/7 trampler was blocked by two 3/3s instead of three, then you could have your creature deals 3 damage to each of the blocking creatures and 1 damage to the defending player.
March 22, 2014 11:59 p.m.
Epochalyptik says... Accepted answer #5
Rather than ask the outcome in any given scenario, you should absorb the principles at work.
When multiple blockers are assigned to the same attacking creature, the active (in this case, attacking) player announces the damage assignment order for those creatures. This is the order in which the attacking creature will assign damage to the multiple blocking creatures. In order to assign damage to any given blocker in the damage assignment order, all creatures before it must have been assigned lethal damage. You can assign more than lethal damage to any given creature, but that means you'll have less damage to distribute to any creatures after it.
For example, you have a 6/6 attacker blocked by a 2/2, a 3/3, and a 4/4. You declare that the damage assignment order will be 2/2, 3/3, and 4/4. You must assign at least 2 damage to the 2/2. Then, if you want to assign damage to the 4/4, you must assign at least 3 damage to the 3/3. You'll only have 1 damage left for the 4/4.
If your attacker has trample, you can assign any excess damage to the defending player. This means that you can assign lethal damage to the defending player after all creatures in the damage assignment order have been assigned lethal damage.
March 23, 2014 12:23 a.m.
Just to clarify, The 6/6 attacker does not do 6 damage to each of the 2/2/, 3/3, or 4/ 4, rather you have 6 damage you can deal to the three creatures. So if I block 2/2 first, I only have 4 damage to 'play' with for the 3/3 or 4/4. Correct?
March 23, 2014 10:47 a.m.
Rhadamanthus says... #7
Right. If you put the 2/2 first in the blocking order then a minimum of 2 damage has to be assigned to it before you can assign the rest of the damage anywhere else.
Epochalyptik says... #1
1) You declare the damage assignment order for the three 3/3 black Zombies. You assign 7 damage across these Zombies. You must assign lethal damage to the first blocker before you can assign any to the next. You'll end up killing two 3/3s, and your 7/7 will die.
2) Same thing. Your 7/7 doesn't have enough power to assign lethal damage to each blocker, so you can't assign any damage to the defending player.
3) Same thing. You can kill only one creature, but your 3/3 will die no matter what.
March 22, 2014 9:39 p.m.