How does invigorate rampage play out against Aether meltdown
Asked by Pappyy1369 7 years ago
SO last night me and my friend just finsihed building him a deck. We were playing and it came time for him to play Electrostatic Pummeler paired with Invigorated Rampage and he chose the first ability on the card to give creature +4/+0 and trample. Then he paid the 3 energy to give it +X/+X where X is equal to its power.When he cast that it gave him a 10/5 creature with trample. I used Aether Meltdown on his Pummeler. How would that have played out?
1) Should he end up with a 2/2 with trample since the meltdown says he gets -4/-0 where rampage gave him +4/+0 and then his double goes through and gets him 2/2or 2) Does he get to 10/5 and then the -4/-0 takes place and he has a 6/5 with trample.
I would like to know how this would work so I'm not playing it wrong :)
Pappyy1369 says... #2
Rhadamanthus That is good to know. We ended up playing it the 2nd way around, but I did declare it after he said he was making the 10/6, but either way it ended up being a final turn next turn I won regardless of either way we make it happen I had blockers for the 6/6 or the 2/2 and swung with flyers. This is definitely good information to know.
Rhadamanthus says... Accepted answer #1
If everything happened in the order you described it then your opponent has a 6/6 with trample (it's a 10/6 after its ability resolves, not a 10/5).
The value of X in Electrostatic Pummeler's ability is determined at the time the ability resolves. Doing something else later in the turn to change the creature's power won't go back and re-calculate the value of X for that instance of the ability. If the Pummeler already had 10 power at the time you played Aether Meltdown then its new power will be 10 - 4 = 6.
However, you could have done this a different way. Since Aether Meltdown has flash you could have cast it in response to your opponent activating the Pummeler's ability. That means the Meltdown would be already attached and reducing Pummeler's P/T at the time the Pummeler's ability calculated the value of X. In that case (assuming no further responses from either you or your opponent) the value of X would end up being just 1 and the Pummeler would be a 2/2 after the ability resolves.
August 11, 2017 1:27 p.m.