Copying Epic Experiment

Asked by andypants040 7 years ago

So I run a Melek, Izzet Paragon EDH that ramps really well and I'm often in a place where I can cast a large Epic Experiment copied at least one other time.

I'm just curious how to resolve all of the spells that will be cast with Epic Experiment. Let's say that X is 10 when I cast it and I am able to copy it one time. Do I have to resolve all the spells I want to cast from one copy before I can start casting spells from the other copy? Or can I choose from all of the exiled spells from either of the copies?

ZomBee_Hunt says... #1

Each instance of Epic Experiment will resolve seprately. So this is how it will go.

Stack will be Epic Experiment then copy of it. The copy will resolve first putting all the instants/sorceries on the stack on top of your original Epic Experiment. Then resolve the stack back down. then resolve your original spell.

January 25, 2017 4:29 p.m.

Neotrup says... Accepted answer #2

For the sake of simplicity I'll assume neither you nor your opponent have responces. You cast Epic Experiment (X=10) and Melek's ability triggers. Melek's ability resolves copying Epic experiment and the stack now has Epic Experiment (X=10) on the bottom and Epic Experiment copy (X=10) on top. The copy resolves, you exile the top 10 cards and choose which instants and sorceries with CMC 10 or less to cast, and in what order. Any triggered abilities trigger (Melek's does not). The stack is now Epic Experiment (X=10) on the bottom, some number of free casted spells above it, and any triggered abilities above them. They'll start to resolve one at a time with the real epic experiment resolving last and exiling another 10 cards for you to cast after all the spells from the copied Epic Experiment resolve.

January 25, 2017 4:30 p.m.

Clockwurk says... #3

No, when a copy of an X spell happens, X is always 0. I believe.

January 25, 2017 9:30 p.m.

Neotrup says... #4

Nope, copying an X cost spell remembers the value of X:

706.2. When copying an object, the copy acquires the copiable values of the original object's characteristics and, for an object on the stack, choices made when casting or activating it (mode, targets, the value of X, whether it was kicked, how it will affect multiple targets, and so on). The "copiable values" are the values derived from the text printed on the object (that text being name, mana cost, color indicator, card type, subtype, supertype, rules text, power, toughness, and/or loyalty), as modified by other copy effects, by its face-down status, and by "as . . . enters the battlefield" and "as . . . is turned face up" abilities that set power and toughness (and may also set additional characteristics). Other effects (including type-changing and text-changing effects), status, and counters are not copied.

January 25, 2017 10:14 p.m.

BlueScope says... #5

@Clockwurk: You're probably confusing this with calculating converted mana costs, where X is almost always treated as 0 - the only exception, however, are spells and abilities on the stack, where X is it's actual value.

So in this case, there's no reason whatsoever that X would be 0.

January 26, 2017 2:56 a.m.

Clockwurk says... #6

Ok thanks

January 26, 2017 12:52 p.m.

This discussion has been closed